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Square Sequence (Posted on 2003-12-19) Difficulty: 5 of 5
When you add all the terms up from this sequence: x² + (x-1)² + 3(x-2)² + (x-3)² + (x-4)² + (x-5)² + 3(x-6)² + (x-7)² ... it will be equal to half of (x³ + x² - x) for any positive even integer x. Prove why this works.

Example: 12² + 11² + 10² + 10² + 10² + 9² +8² + 7² + 6² + 6² + 6² + 5² + 4² + 3² + 2² + 2² + 2² + 1² if x = 12.

Note: The coefficients go 1, 1, then 3, then 3 1s, then 3, then 3 1s. The coefficients go in this order, even if there are coefficients left when the sequence stops. For example, with 6, the coefficients would go 1,1,3,1,1,1.

  Submitted by Gamer    
Rating: 2.5000 (4 votes)
Solution: (Hide)
Charlie gave a proof by induction here, and a way to prove it without knowing the forumla is supplied here.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
More about approachGamer2007-02-19 15:37:37
different approachLee2003-12-22 06:54:26
re: Sorry, my mistakeGamer2003-12-20 20:41:47
Sorry, my mistakePenny2003-12-20 10:39:36
re(3): proofGamer2003-12-20 07:36:11
Some Thoughtsre(2): proofPenny2003-12-20 00:13:13
re: proofGamer2003-12-19 18:27:34
SolutionproofCharlie2003-12-19 16:33:44
SolutionSolution (no computer assistance used)Penny2003-12-19 15:33:16
if x=3???rerun1412003-12-19 12:38:22
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