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Only Isosceles (Posted on 2005-02-13) |
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Arrange 8 points in 3-space so that for each of the 56 triples of points that they determine, at least two of the three distances between points in the triple are equal.
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Submitted by David Shin
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Rating: 4.5000 (4 votes)
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Solution:
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(Hide)
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Start with a regular pentagon inscribed in the unit circle in the x-y plane, together with the origin; this places six of the points. Let the remaining points be (0,0,1) and (0,0,-1). In the comments, Charlies explains why this configuration works.
This problem is due to Paul Erdos. It is not known whether the 8-point set of the solution is unique. |
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