Knight, Knave, and Liar Party (Posted on 2005-02-14)

	Submitted by Dustin
Rating: 4.0000 (3 votes)
Solution:	(Hide)
Any time you know the identities of two consecutive persons, you can work backwards and see if it checks out. Assume A is a knight. He calls B a knave. Now, work backwards to discover that B, a knave, makes two false statements. Therefore, the assumption that A is a knight is false. Assume A is a knave. One of his two statments is true. Assume it's the B is a knave one. Now, with two consecutive persons, work backwards to discover that knave B makes two false statements. OK, now assume it's the C is a knave one. B is not a knave, so either a knight or a liar. Can't be a knight, because he falsely calls C a liar. Work backwards to discover knave C tells two lies. Since A can't be a knight, a truth-lie knave, or a lie-truth knave, he must be a liar. G and H correctly say A is a liar, so neither one of G and H is a liar. So F, saying they both are, must be lying himself. Since A lies saying B is a knave, B must not be a knave. Since H calls B a knave, he must be lying in that statement, so H is a knave. Since A and H are consecutive, and you have already eliminated the other possibilities for A, the solution that follows from working backwards must be correct. And indeed, when you check A's and H's statements to make sure they match, they do. Final conclusion: Knights: B and G. Knaves: D, E, and H. Liars: A, C, and F.

	Subject	Author	Date
	answer	K Sengupta	2007-11-24 10:39:04
	Whom to trust	scott	2005-08-02 13:44:25
	Solution?	Angela	2005-02-15 11:30:13
	Solution	Avin	2005-02-14 19:52:42