Discriminants (Posted on 2005-05-24)

	Submitted by Jer
Rating: 3.5000 (4 votes)
Solution:	(Hide)
Only integers congruent to 0 or 1(mod 4) are possible. If b is even b^2 is a multiple of 4 so b^2-4ac is a multiple of 4 If b is odd, then b=2k+1 so b^2 is 4k^2 + 4k + 1 which is congruent to 1(mod4) and so b^2-4ac is too.

	Subject	Author	Date
	Puzzle Solution	K Sengupta	2009-01-22 13:58:12
	A further note	Jer	2005-06-08 16:56:26
	re(2): Four	Bractals	2005-05-27 05:02:39
	re: Four	Richard	2005-05-25 09:10:41
	Four	Bractals	2005-05-25 05:24:26
	re: Solution (no explanation given)	Richard	2005-05-24 22:47:51
	Solution (no explanation given)	Old Original Oskar!	2005-05-24 14:11:21