Sinking Ball (Posted on 2006-01-03)

	Submitted by Brian Smith
Rating: 2.0000 (1 votes)
Solution:	(Hide)
First, the volume of the ball is (4/3)*pi*(2 cm)^3 = 32*pi/3 cm^3 The gives the density of the ball as equal to (mass ball)/(volume ball) = (40g)/(32*pi/3 cm^3) = 15/(4*pi) g/cm^3 = ~1.19 g/cm³. Barring other forces, the ball will sink and settle on the bottom of the cup. Noting that the initial water level is higher that the diameter of the ball, the entire ball will be submerged, and therefore the volume of water displaced is equal to the volume of the ball itself. This volume (4/3*pi*r³) is divided by the cup base area (pi*r²;different r) to determine how much the water level rises. This gives (4/3*pi*2³)/(pi*4²) = (4*2³)/(3*4²) = 2/3 cm

	Subject	Author	Date
	Answer	K Sengupta	2008-03-19 11:22:05
	Solution	Ansh	2006-10-07 14:48:47
	No Subject	alex	2006-08-07 20:51:27
	re(3): My thoughts	MindRod	2006-01-03 22:31:17
	re: My thoughts	MindRod	2006-01-03 22:26:53
	re(2): My thoughts	Percy	2006-01-03 20:50:02
	re: My thoughts	Hugo	2006-01-03 16:58:49
	My thoughts	Fletch	2006-01-03 09:32:06