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That's a lotta numbers! (Posted on 2006-04-14) Difficulty: 2 of 5
Consider all nine-digit numbers consisting of one each of the digits 1 through 9.

What is the sum of these numbers?

  Submitted by Jer    
Rating: 3.2500 (4 votes)
Solution: (Hide)
Each number appears in each position 8! times. 1+2+...+9=45 so the solution is 45*111111111*8!= 201599999798400

Comments: ( You must be logged in to post comments.)
  Subject Author Date
That's a lotta numbershugh2006-04-19 00:06:14
I thinkTim2006-04-17 01:14:25
re: Another ViewpointK Sengupta2006-04-15 20:38:06
SolutionA solutionDej Mar2006-04-15 06:14:30
SolutionAnother ViewpointRichard2006-04-14 15:57:23
Solutionre: Is this it? -- computer verificationCharlie2006-04-14 15:03:32
Some ThoughtsGeneralised Result: Detailed Solution Not GivenK Sengupta2006-04-14 12:28:12
Solution The SolutionK Sengupta2006-04-14 12:19:36
Hints/TipsIs this it?tomarken2006-04-14 11:49:48
Hints/TipsSome Hints For Solving The ProblemK Sengupta2006-04-14 09:45:40
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