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That's a lotta numbers! (
Posted on 2006-04-14
)
Consider all nine-digit numbers consisting of one each of the digits 1 through 9.
What is the sum of these numbers?
Submitted by
Jer
Rating:
3.2500
(4 votes)
Solution:
(
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Each number appears in each position 8! times. 1+2+...+9=45 so the solution is 45*111111111*8!= 201599999798400
Comments: (
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Subject
Author
Date
That's a lotta numbers
hugh
2006-04-19 00:06:14
I think
Tim
2006-04-17 01:14:25
re: Another Viewpoint
K Sengupta
2006-04-15 20:38:06
A solution
Dej Mar
2006-04-15 06:14:30
Another Viewpoint
Richard
2006-04-14 15:57:23
re: Is this it? -- computer verification
Charlie
2006-04-14 15:03:32
Generalised Result: Detailed Solution Not Given
K Sengupta
2006-04-14 12:28:12
The Solution
K Sengupta
2006-04-14 12:19:36
Is this it?
tomarken
2006-04-14 11:49:48
Some Hints For Solving The Problem
K Sengupta
2006-04-14 09:45:40
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