All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Three Altitudes (Posted on 2007-01-15) Difficulty: 3 of 5
If the lengths of the altitudes of a triangle are 4, 5, and 6, what is the area of the triangle?

Can you generalize?

  Submitted by Dennis    
Rating: 3.0000 (1 votes)
Solution: (Hide)
If h, j, and k represent the lengths of the altitudes of a triangle, the area of the triangle is given by the equation:

A=(hjk)^2/sqrt(2(hjk)^2(h^2+j^2+k^2)-((hj)^4+(hk)^4+(jk)^4))

The above formula is derived by solving simultaneously the six pythagorean equations involving the altitudes and the segments of the sides they partition.

Letting h=4, j=5, and k=6 --> A=3600/sqrt(57239) --> the sides have lengths 1200/sqrt(57239), 1440/sqrt(57239), and 1800/sqrt(57239).

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Puzzle ThoughtsK Sengupta2024-05-27 11:55:37
No SubjectAmanda2007-01-16 00:26:27
Solutionresearched solutionCharlie2007-01-15 23:21:07
SolutionBractals2007-01-15 17:43:05
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information