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A problem to end all shift-a-digit problems (Posted on 2007-03-26) Difficulty: 3 of 5
Prove that there exists no natural number such that shifting its first digit to the end, multiplies it by 5, 6, or 8.

  Submitted by e.g.    
Rating: 4.0000 (1 votes)
Solution: (Hide)
The simplest way to see this is to note that (1) the first digit can only be 1, and (2) no multiple of 5, 6, or 8, ends with 1.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionPuzzle SolutionK Sengupta2022-05-11 01:35:33
re: Something of a solution (one example)Dej Mar2007-03-27 01:03:34
Some ThoughtsSomething of a solution.Leming2007-03-26 13:34:01
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