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A problem to end all shift-a-digit problems (Posted on 2007-03-26) |
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Prove that there exists no natural number such that shifting its first digit to the end, multiplies it by 5, 6, or 8.
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Submitted by e.g.
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Rating: 4.0000 (1 votes)
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Solution:
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(Hide)
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The simplest way to see this is to note that (1) the first digit can only be 1, and (2) no multiple of 5, 6, or 8, ends with 1. |
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