A Point in a Triangle (Posted on 2007-04-12)

	Submitted by Brian Smith
Rating: 3.0000 (1 votes)
Solution:	(Hide)
Let the lengths of PA, PB, and PC be x, y, and z respectively. Using the law of cosines, three equations can be written: x^2+xy+y^2 = AB^2 z^2+zy+y^2 = BC^2 x^2+xz+z^2 = AC^2 A brute force search of values x, y, and z finds a smallest solution of: x=195, y=264, z=325, AB=399, AC=455, BC=511

	Subject	Author	Date
	Puzzle Thoughts	K Sengupta	2024-06-05 01:40:40
	re(5): on another look	Nishant	2007-04-14 04:01:14
	re(4): on another look	Charlie	2007-04-13 16:46:25
	re(3): on another look	Nishant	2007-04-13 15:04:17
	re(2): on another look	Brian Smith	2007-04-13 12:24:27
	re: on another look	Nishant	2007-04-13 10:21:29
	on another look	xdog	2007-04-13 08:35:48
	Another look	Nishant	2007-04-13 02:58:50
	solution (spoiler)	Charlie	2007-04-12 15:40:14