perplexus.info :: Numbers : Consecutive Near Palindromes

Consecutive Near Palindromes (Posted on 2008-02-13)

Find a set of four consecutive six digit numbers which satisfies the following:

The last four digits of the first (smallest) number form a palindrome.
The last five digits of the second number form a palindrome.
The second through fifth digits of the third number form a palindrome.
The fourth (largest) number is a palindrome.

Submitted by Brian Smith

Rating: 3.3333 (3 votes)

Solution: (Hide)

The intended solution, which is posted in the comments, is:
198888 198889 198890 198891
But, if one were to abuse the notion of 'palindrome' then a second solution can be found:
199999 200000 200001 200002

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Two Solutions	Larry	2023-02-28 08:39:35
brute force perl solution	Moira	2009-01-22 00:50:47
re(2): Are there more?	brianjn	2008-02-14 03:46:35
re: Are there more?	Charlie	2008-02-14 02:24:39
solution	K Sengupta	2008-02-13 22:44:10
Are there more?	brianjn	2008-02-13 22:41:19
Great puzzle	Josie Faulkner	2008-02-13 16:30:07
Solution	Dej Mar	2008-02-13 12:08:57
solution (spoiler)	Charlie	2008-02-13 11:31:25

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