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Factorial and a Square (Posted on 2008-02-23) |
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If a and p are positive integers, then solve for (a,p):
a2=p!
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Submitted by Praneeth
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Rating: 2.0000 (4 votes)
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Solution:
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(Hide)
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In prime factorization form of p!, every power of prime should be even.
For p>1, there exists at least a prime between p/2 and p(including p). So, there exists a prime whose power is 1 (This is concluded using the formula).
So, for p>1, no factorial can be a perfect square.
The only solution is a=1 and p=1 in positive integers. |
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