perplexus.info :: Numbers : Square = Square + Square

Square = Square + Square (Posted on 2008-08-26)

Determine all 6 digit perfect squares such that the first three digits form a perfect square as do the last three.

The square formed by the first three digits may not have leading zeroes.

Submitted by brianjn

Rating: 2.5000 (4 votes)

Solution: (Hide)

256036 256 036 576081 576 081 144400 144 400 225625 225 625 324900 324 900 -------------------------------------------------- This was my program. While its output was in the format above, I did have to add the leading zeroes for 36 and 81. OPEN "6sqr.txt" FOR OUTPUT AS #1 FOR a = 1 TO 31 FOR b = 10 TO 31 c= b^2*10^3 + a^3 IF sqr(c) = int(sqr(c))THEN PRINT c, b^2, a^2 PRINT #1, c, b^2, a^2 ENDIF NEXT NEXT CLOSE 1

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Puzzle Solution	K Sengupta	2022-08-20 13:09:04
re(2): Solution - an	Dej Mar	2008-08-26 23:41:21
re: Solution - an "imperfect" square	brianjn	2008-08-26 20:32:35
Solution	ed bottemiller	2008-08-26 13:35:36
Solution	Dej Mar	2008-08-26 13:25:32
re: Solution - brute force	Charlie	2008-08-26 11:50:39
Solution - brute force	andre	2008-08-26 11:15:47

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