super powerful pandigitals (Posted on 2009-02-24)

	Submitted by Daniel
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As Charlie first pointed out the answer to the first part is 3^15 is the largest power of 3 that can divide a 0 to 9 pandigital number. In researching this problem I simply used a spreadsheet and did not use an exaustive computer program and thus made a slight miscalculation that caused me to belive that 3^14 was the largest power thus leading to the following pandigitals 3410256897 5361708249 5902183746 6820513794 7246198035 8145396207 8269753401 9145036728 9537240186 As for the second part I initially was refering to 5902183746 which when divided by 3^14 leads to 1234 a 1 to 4 pandigital number. Which Charlie also discoverd. Some other unique properties were discovered by Jer, Ed Bottemiller, and Dej Mar.

	Subject	Author	Date
	Puzzle Thoughts	K Sengupta	2024-03-09 20:36:20
	Interesting properties?	Dej Mar	2009-02-24 17:04:24
	H-R number!	ed bottemiller	2009-02-24 16:52:42
	re(2): Uncertain	Charlie	2009-02-24 16:47:42
	re: Uncertain	Daniel	2009-02-24 14:51:15
	Uncertain	ed bottemiller	2009-02-24 14:35:47
	An uninteresting property.	Jer	2009-02-24 13:59:23
	Hmmmm.... (computer solution? -- spoiler)	Charlie	2009-02-24 12:36:51