If point D is taken as the origin, and the sides of the squares are unit length, then point G is at (sqrt(3)/2, -1/2), and point F is at (sqrt(3)/2 + 1/2, sqrt(3)/2 - 1/2), while point C is at (0, -1). This makes line CF have a slope of 1, and at an angle of 45° with CD, adding to the 45° of DCA, making the total angle ACF equal 90°.
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