perplexus.info :: Numbers : Four + Five = Nine

Four + Five = Nine (Posted on 2009-07-26)

Substitute each of the capital letters in bold by a different base ten digit from 0 to 9 to satisfy this alphametic equation. None of the numbers can contain any leading zero.

FOUR + FIVE = NINE, where FOUR is divisible by 4, FIVE is divisible by 5 and, NINE is divisible by 3.

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

The required letter to digit assignment is as follows:
F...O...U...R...I...V...E...N 1...9...6...0...4...7...5...3
So that:
FOUR=1960.
FIVE=1475.
NINE=3435.
For an explanation, refer to the almost perfect solution submitted by xdog in this location.
*** The only discrepancy there is that I should be 4, rather than 2, which was pointed out by brianjn in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
re: Answer	brianjn	2009-07-27 00:03:51
Answer	xdog	2009-07-26 16:19:23

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