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Number = Sum (Digit)*Product (Digit) (Posted on 2010-06-21) Difficulty: 2 of 5
N is a positive base ten integer having at least 2-digits but at most 4-digits, which is obtained by multiplying the sum of its digits with the product of its digits. It is known that N cannot contain any leading zero.

Determine all possible value(s) of N.

  Submitted by K Sengupta    
Rating: 4.0000 (2 votes)
Solution: (Hide)
135 and 144 are the only possible values of N, that satisfy the given conditions, since:
(1+3+5)(1*3*5) = 9*15 = 135
(1+4+4)(1*4*4) = 9*16 = 144

For an explanation, refer to:

The solution submitted by Jer in this location.

The solution submitted by Charlie in this location.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Some Thoughtsre: No Subject... Too late to be sorry...Ady TZIDON2010-06-24 10:25:15
this 'N thated bottemiller2010-06-22 12:55:01
re: No SubjectCharlie2010-06-21 23:20:08
re: Solution & thoughtsDaniel2010-06-21 21:11:59
No Subjected bottemiller2010-06-21 17:09:38
re: Count em up!Charlie2010-06-21 16:32:42
Count em up!ed bottemiller2010-06-21 15:10:20
Solutionre: Solution & thoughtsCharlie2010-06-21 14:22:24
Solution & thoughtsJer2010-06-21 14:09:07
Non-leading zero??ed bottemiller2010-06-21 13:28:57
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