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A Magic Die (Posted on 2010-06-10) Difficulty: 1 of 5
A magic die, with the numbers 1, 2, 3, 4, 6, and 7 on its six faces, is rolled.
After this roll, if an odd number appears on the top face, all odd numbers on the die are squared.
If an even number appears on the top face, all the previously odd numbers are increased by 3 and then all the even numbers are halved and then squared.
If the given die changes as described and assuming a perfectly balanced die,
what is the probability that the number appearing on the second roll
of the die is 1 mod 8?

  Submitted by Ady TZIDON    
Rating: 4.5000 (2 votes)
Solution: (Hide)
Solution:
1 2 9 4 6 49 > ==>1/2
or
4,1,6,4,9,10 = > 4,1,9,4,9,25 ==2/3

1/2*(1/2+2/3)=7/12

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionMagic die solutionDan Rosen2010-06-16 13:27:01
SolutionOz got it (maybe)Dej Mar2010-06-11 04:06:32
Hints/TipsReconsider your solutionsAdy TZIDON2010-06-10 17:42:07
Can Merlin settle this?ed bottemiller2010-06-10 13:21:46
re: analytical solutioned bottemiller2010-06-10 12:51:33
re: analytical solutionCharlie2010-06-10 12:47:59
Assumptionsed bottemiller2010-06-10 12:31:45
analytical solutionDaniel2010-06-10 12:03:08
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