perplexus.info :: Probability : Triangular Cubes II

Triangular Cubes II (Posted on 2010-12-21)

Three points have been chosen randomly from the vertices of a tesseract (4-cube).

What is the probability that they form (a) an acute triangle; (b) a right triangle?

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

(a) The required probability is 2/7.
(b) The required probability is 5/7.
For an explanation, refer to the solution submitted by Charlie in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
re: computer solution	Charlie	2010-12-21 13:51:41
computer solution	Charlie	2010-12-21 13:48:39

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