perplexus.info :: Numbers : A repunit number

A repunit number (Posted on 2011-12-26)

3 integers form an arithmetic progression with d=2 i.e. a, a+2, a+4.
The sum of their squares is a 4-digit number divisible by 1111.
List all possible triplets.

Submitted by Ady TZIDON

Rating: 4.0000 (1 votes)

Solution: (Hide)

There are 2 triplets: (41,43,45) and (-45,-43,-41)

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
re(2): is there a mistake in the puzzle?	Charlie	2011-12-26 14:54:09
Solution (Spoiler)	Larry	2011-12-26 11:32:42
re: is there a mistake in the puzzle?	Jer	2011-12-26 11:29:12
Solution	Jer	2011-12-26 11:25:28
is there a mistake in the puzzle?	Charlie	2011-12-26 10:59:43

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