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Origamic II (Posted on 2012-03-18) Difficulty: 3 of 5
This is in continuation of Origamic.

A sheet of paper has the exact shape of a rectangle (denoted by ABCD) where AB is the longer side and AD is the shorter side. The vertex A is folded onto the vertex C, resulting in the crease EF (E on AB and F on CD).

The paper is thereafter unfolded and, the vertex A is folded onto F, resulting in the crease KJ.

Determine separately the ratio of the longer side (AB) of the rectangle to the shorter side (AD), whenever:

(i) K coincides with D and, J is on AE.

(ii) J coincides with B and, K is on AD.

(iii) J coincides with E and, K is on AD.

  Submitted by K Sengupta    
Rating: 5.0000 (1 votes)
Solution: (Hide)
(i) 1 + √2= 2.4142 (approx.)
(ii) √(1 + 2*√3/3)= 1.4679 (approx.)
(iii) √3 = 1.7321 (approx.)

For an explanation, refer to the solution submitted by Bractals here.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionSolutionBractals2012-03-18 13:24:13
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