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| Angles missing (Posted on 2012-07-09) |
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What are the angles of the right-angled triangle, whose area is 1/(2*pi)
of said triangle's circumscribing circle's area?
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Submitted by Ady TZIDON
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Rating: 4.0000 (1 votes)
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Solution:
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(Hide)
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Let the triangle be ABC, C=90degrees.
R- radius of the circle.
S=pi*R^2/2pi=(R^2)/2
On the other hand S=1/2*2RcosA*2RsinA=R^2*sin2A
sin2A=1/2
2A=30
A=15 , B=75 degrees
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Subject |
Author |
Date |
 | solution | Charlie | 2012-07-09 12:17:43 |
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