What a waist (Posted on 2003-05-28)

	Submitted by DJ
Rating: 4.4444 (9 votes)
Solution:	(Hide)
36¼-23-33¾ and 36-22½-34½ Since the tape is only accurate to ¼" for all measurements (meaning each measurement is an integer multiple of ¼"), and each the two runners-up waist is two-thirds of the other's hips, then both hip measurements must be multiples of ¾". These numbers are between 33" and 35" (non-inclusive), and the only values that fit these parameters are 33¾", two-thirds of which is 22½", and 34½", two-thirds of which is 23". So, one of the girls in question has a 23" waist and a 33¾" hip measurement; the other has a 22½" waist and 34½" hips. We also know that the sum of all three measurements is the same for each girl. For the winner, this is 36+23+34=93". So, the remaining (bust) measurement for the first girl above is 93-23-33¾=36¼", and for the second, 93-22½-34½=36". Therefore, the two runners-up must have measurements : 36¼-23-33¾ and 36-22½-34½

	Subject	Author	Date
	Puzzle Solution	K Sengupta	2007-10-26 05:19:19
	re: Solution	DJ	2003-05-29 16:01:19
	Solution	Bryan	2003-05-28 09:51:38
	Solution	Clinton Heath	2003-05-28 09:26:47