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Four Reals (Posted on 2013-05-10) Difficulty: 2 of 5


If a, b, c, and d are real numbers, then prove that

(a + b + c + d) - (a2 + b2 + c2 + d2) ≤ 1.

  Submitted by Bractals    
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Solution: (Hide)

For every real x,

   0 ≤ (x - ½)2 = x2 - x + ¼
     or
   x - x2 ≤ ¼ 

Therefore,

   a - a2 ≤ ¼
   b - b2 ≤ ¼ 
   c - c2 ≤ ¼ 
   d - d2 ≤ ¼ 

Adding these gives

   (a + b + c + d) - (a2 + b +2 c2 + d2) ≤ 1. 

QED

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  Subject Author Date
Easy wayJer2013-05-10 12:05:59
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