perplexus.info :: Probability : Consecutive Placement

Consecutive Placement - Not (Posted on 2014-12-01)

Positive integers from 1 to 8 inclusively are randomly placed on the faces of a regular octahedron with each face being assigned a different number. For the purposes of the puzzle, 8 and 1 are considered as consecutive numbers.

Determine the probability that no two consecutive numbers are placed on faces that share an edge.

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

The required probability is: 10/840 = 1/84 ~= 0.01190476190.
For an explanation, refer to the computer program assisted solution submitted by Charlie in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
re: computer assisted solution	K Sengupta	2024-04-09 02:51:49
computer assisted solution	Charlie	2014-12-01 16:23:18

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