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1-2-3 Remainder Resolution (Posted on 2016-02-16) Difficulty: 3 of 5
Abe challenges Bee to determine a 3-digit positive integer N.
It is known that the number formed by the last two digits of N when divided by 9, yields a remainder of 3.

Abe makes the following statements, precisely one of which is false:
  1. N divided separately by each of 2, 4, 6, and 8 yields a remainder of 1.
  2. N divided separately by each of 5 and 7 yields a remainder of 2.
  3. N divided separately by each of 5 and 11 yields a remainder of 3.
Determine the value of N from the above statements and given clues.

See The Solution Submitted by K Sengupta    
Rating: 4.6667 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Hints/Tips re: d3 answer | Comment 7 of 12 |
(In reply to d3 answer by Steve Herman)

...

3) If statement 3 is true, then (100y + 9z +3) mod 11 = 3 = (100y + 9z + 3) mod 5
   Then 9z = 0 mod 5 and y = 2z mod 11.  wrong
   But 9z = 0 mod 5 implies z = 0 or 5, and this fails if y = 2z mod 11.
   So statement 3 is false.
that's why you lost  993

  Posted by Ady TZIDON on 2016-02-16 12:34:43
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