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Hexagon Hinder 2 (Posted on 2016-05-06) Difficulty: 3 of 5
The hexagon PQRSTU is such that:

(1) All its vertices lie on a circle, and:
(2) PQ = RS = TU, and:
(3) the diagonals PS, QT, RU meet at a point.

N is the intersection of PS and RT


No Solution Yet Submitted by K Sengupta    
Rating: 4.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionSolutionHarry2016-05-08 15:31:37
Some ThoughtsObservationJer2016-05-07 21:35:32
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