All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes
Chocolate! (Posted on 2002-06-12) Difficulty: 2 of 5
I can't take credit for this. It was submitted to a quiz page on the CBC's (Canadian Broadcasting Co) website by Professor Maria Klawe of the Computer Science department at the University of British Columbia. But I thought our group would enjoy it.

Remember when a bar of plain milk chocolate was scored to allow you to break it evenly into smaller pieces?

What is the smallest number of breaks needed to divide a 4 by 8 chocolate bar into single squares, where each break splits any one of the pieces along an original horizontal or vertical line of the bar? Your answer should explain why your number is the smallest possible.

See The Solution Submitted by TomM    
Rating: 3.6000 (10 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: bob is right (where did the other row go?) | Comment 11 of 13 |
(In reply to bob is right by Jon)

8 x 3 is only 24 little bars. The puzzle calls for 8x4 little bars. You have 3 breaks to break apart 4 strips of 8, and each of those 4 strips of 8 requires 7 breaks. That's 3 + 4 x 7 = 31.

The other way, making 8 strips of 4, requires 7 breaks initially, and then each of the 8 strips of 4 requires 3 breaks, so 7 + 8 x 3 = 31.
  Posted by Charlie on 2003-04-11 10:16:31

Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2019 by Animus Pactum Consulting. All rights reserved. Privacy Information