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 1,3,8 ...extend! (Posted on 2017-01-26)
The set (1,3,8) has this peculiar feature:

Multiply any two of these numbers together and add 1 and you'll always get a perfect square:

1+ 1 × 3 = 4
1 + 1 × 8 = 9
1 + 3 × 8 = 25

a. Add to the above set a 4th integer, thus enabling 3 additional equalities.
b. Can you show why no 5th member maintaining the above feature exists?

 No Solution Yet Submitted by Ady TZIDON Rating: 5.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
 Subject Author Date The number Math Man 2017-02-19 21:09:15 re: results from some reading....more Ady TZIDON 2017-01-27 00:58:18 results from some reading xdog 2017-01-26 17:03:43 computer finding Charlie 2017-01-26 14:38:53
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