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Areas ratio (Posted on 2017-02-24) Difficulty: 3 of 5
From any point P within a given triangle, say ABC lines are drawn parallel to the two sides, meeting the 3rd side on points D, E.

Show that the mean value of triangle PDE's area is one-sixth ABC'S area.

The solver may assume that each point within ABC may be chosen with the same probability as others (i.e. uniform distribution).

No Solution Yet Submitted by Ady TZIDON    
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  Subject Author Date
SolutionsolutionCharlie2017-02-24 11:18:28
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