(In reply to hint based somewhat on computer findings
In fact, of the 2^31 = 2147483648 32-binary digit numbers without leading zero, C(31,14) = 265182525 have as many 1's as 0's. That's about 1 in 8.1. Of course not all those are pandigital in base 10, but it gives and idea of the odds involved in finding one by chance.
Posted by Charlie
on 2016-12-13 14:11:27