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Pythagoras' corner (Posted on 2017-06-16) Difficulty: 3 of 5
Slice off the corner of a right rectangular prism so that the result is a tetrahedron with three right triangular faces mutually perpendicular to each other. The fourth face is a triangle formed by the hypotenuses.

Prove: The sum of the squares of the areas of the three right triangles is equal to the square of the area of the fourth.

No Solution Yet Submitted by Jer    
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Some Thoughts Cutting Corners? | Comment 2 of 3 |

Is this problem the same as http://perplexus.info/show.php?pid=9293&cid=53702.

I didn't see it in the queue or I would have mentioned it.


  Posted by broll on 2017-06-17 07:03:51
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