Given that the pandigital is composed of the factors in 1 through 22 excluding 19, requires the pandigital to be a multiple of 12252240. There are four such 10digit pandigital numbers:
12252240×199 = 2438195760
12252240×309 = 3785942160
12252240×388 = 4753869120
12252240×398 = 4876391520
An interesting fact is that the pandigital 4876391520 is exactly double that of the pandigital 2438195760.

Posted by Dej Mar
on 20171229 22:10:11 