(In reply to Not feeling literal
by Steve Herman)
I red the puzzle literally. As 2n+1 is always odd, removing one leave always n pairs of numbers.
But only if the term been remove is the first, or that in the middle or the last, you have pairs that can be arranged having the same sum.
That's why I post before:
1, n+1, 2n+1
Edited on February 14, 2018, 2:20 am
Posted by armando
on 2018-02-14 02:15:09