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 Intersection of Perps (Posted on 2018-01-14)

Let AB and PQ be chords of circle Γ where AB is arbitrary and
PQ is the perpendicular bisector of AB. Let C be a point on Γ
distinct from points A and B. Let I be the incenter of ΔABC. Let
H be the intersection of the perpendicular bisectors of line segments
IA and IB.

Prove that H is either the point P or the point Q.

 See The Solution Submitted by Bractals No Rating

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 re: Solution Comment 3 of 3 |
(In reply to Solution by Jer)

I agree that the ray CI intersects the line PQ at point P and the point H ( the intersection of the perpendicular bisectors of line segments IA and IB ) lies on line PQ, but why does P = H?

I know why now, that's why I edited my first post.

Edited on January 16, 2018, 11:21 am
 Posted by Bractals on 2018-01-16 06:25:25

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