To determine who plays first in a game of Scrabble, each player draws a tile and the one closest to A wins, except if one draws a blank tile. A blank tile beats any letter.
If there are only two players, what is the probability they both draw the same letter or both draw a blank?
The letters (and counts) are
E (12); A, I (9); O (8); N, R, T (6); D, L, S, U (4); G (3); B, C, F, H, M, P, V, W, Y (2); J, K, Q, X, Z (1); and 2 blanks.  100 tiles in all.
Bonus: What if there are more than two players: what is the probability of a tie for who plays first? (subsequent play is to the left so 2nd, etc. player are not determined by the draw).
(In reply to
re(3): No Subject by Charlie)
And he considers also the blanks. So the only point I see is if the total number o tiles is 100 the formulas for a letter with n tiles should be n/100*(n1)/99.
So (12*11+2*9*8+ .…+ 2*2*1)/9900
Perhaps Jer consider that each player has 100 tiles.

Posted by armando
on 20180125 05:22:48 