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A pandigital set (Posted on 2018-04-14) Difficulty: 2 of 5
A+B=CD
E+F=G
H+I=J


Assign 0-9 digits to the letters A-J to make the above equations true.
REM: Choose only the solutions in which A>B; E>F & H>I.

No Solution Yet Submitted by Ady TZIDON    
Rating: 5.0000 (1 votes)

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hand solution | Comment 2 of 5 |
By inspection C=1 and D=0. Then G (say)=9.  Since the sum of all the digits is 45, H+I+J=16 and J=8.  Then (A,B) are (7,3) or (6,4). Either choice uniquely determines (E,F) and the remaining digits conveniently fit H+I=J.

 

  Posted by xdog on 2018-04-14 20:16:04
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