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A pandigital set (
Posted on 20180414
)
A+B=CD
E+F=G
H+I=J
Assign 09 digits to the letters AJ to make the above equations true.
REM: Choose only the solutions in which A>B; E>F & H>I.
No Solution Yet
Submitted by
Ady TZIDON
Rating:
5.0000
(1 votes)
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hand solution
 Comment 2 of 5 
By inspection C=1 and D=0. Then G (say)=9. Since the sum of all the digits is 45, H+I+J=16 and J=8. Then (A,B) are (7,3) or (6,4). Either choice uniquely determines (E,F) and the remaining digits conveniently fit H+I=J.
Posted by
xdog
on 20180414 20:16:04
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