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From primes to palindromes (Posted on 2018-05-16) Difficulty: 3 of 5

No Solution Yet Submitted by Ady TZIDON    
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OEIS crossreferencing | Comment 2 of 4 |
The palindromic cubes
begins 0, 1, 8, 343, 1331, 1030301, ...

Number of ways of representing n as the sum of one or more consecutive primes:

Shows one solution for 8 (given) none for 343, one solution for 1331 (as shown by Dej Mar).

There is a table that goes to 10000, which is insufficient for 1030301.
I searched for this a bit with a table of primes.  If 1030301 can be written as the sum of consecutive primes, there must be at least 13 of them.

(I also wonder what a trivial case would look like.)

Edited on May 16, 2018, 2:21 pm
  Posted by Jer on 2018-05-16 10:06:09

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