Given a triangle ABC and a straight line L.

Find the point P on L such that
PA²+PB²+PC² is the smallest.

If we call L the x-axis we can arbitrarily represent any triangle as three points above this axis, at heights y1, y2, and y3. Let us put the first point on the y-axis (x1=0) and place the other two at x2 and x3 so the three points of the triangle are (0,y1) (x2,y2), (x3,y3). Placing point P on the x-axis at x, that is (x,0). Note that this arrangement maintains the generality of the problem. (Con't)

Edited on June 24, 2018, 2:07 pm

Posted by Steven Lord on 2018-06-04 23:48:05