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A number well defined (
Posted on 20181025
)
Half of my 2digit number
N
is also a 2digit number,
one of its digit being the sum of
N
's digit, the other their difference.
All 4 digits are different.
Find my number.
No Solution Yet
Submitted by
Ady TZIDON
No Rating
Comments: (
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Algebraic Solution
 Comment 2 of 5 
Let N = 10a + b
Let N/2 = 10c + d
Then 10a + b = 20c + 2d
c cannot be the sum of the digits, so d = a + b
Then 8a  b = 20c
If c = a  b, then this becomes 19 b = 12a, and the only solution in single digits is (0,0).
So c = b  a.
Then 28a = 21b
4a = 3b
Solution = (3,4)
N = 34 and N/2 = 17
. Only solution
Posted by
Steve Herman
on 20181025 09:33:06
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