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Nine Digits in a Grid (Posted on 2018-12-17) Difficulty: 2 of 5
Each letter in the grid represents a different digit from 1 through 9. What is each, given that

  1. A is smaller than B and A*B is a 2-digit number in which the second digit is two more than the first.
  2. One of the rows contains three consecutive digits, not necessarily in order.
  3. D+E = F
  4. E^2 = G
  5. H = 7
A B C
D E F
G H I

From Mensa Puzzle Calendar 2018 by Fraser Simpson, Workman Publishing, New York. Puzzle for December 11.

See The Solution Submitted by Charlie    
Rating: 3.5000 (2 votes)

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Solution Explanation to Puzzle Answer Comment 3 of 3 |
(In reply to Answer by K Sengupta)

The simultaneous cryptarithmetic equations: 

                              A+2=B, D+E=F, E^2=G, H=7 solve as:

A  B  D  E  F  G   H
1   3  6  2   8  4   7
2   4  5  3   8  9   7
3   5  6  2   8  4   7
4   6  2  3   5  9   7
4   6  5  3   8  9   7
6   8  1  2   3  4   7
6   8  1  3   4  9   7
6   8  2  3   5  9   7
6   8  3  2   5  4   7

Case 1: A, B C are consecutive in any order.
All the nine rows lead to a cryptarithmetic contradiction in some form or another.

Case 2-: D, E, and F are consecutive  in any order.
We observe that D=1, E=2, F=3 in the 6th row. . Therefore, (8,6,1,2,3,4,7) is a solution. But, then C can assume any of the two unassigned values: 5 or 9. This is a contradiction.

Cae 3: G, H, and I are consecutive in any order. 
From row 7, we observe that:
ABDEFGH
4623597
so the middle digit 8 is unassigned. So, for I=8 ,we have G, H and I as consecutive in an arbitrary order.
Our assignment is now:
ABDEFGHI
46235978
The only unassigned digit is 1 which is assigned to the lone unassigned  letter, that is, C.

Consequently our required solution is now as follows:

4  6  1
2  3  5
9  7  8

****************** Quod Erat Demonstrandum *******************

Edited on April 7, 2022, 9:24 pm
  Posted by K Sengupta on 2022-04-07 01:23:25

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