6 cards, labeled 1,2, ...6, are randomly put in 3 different envelopes, at least one card in each.

Evaluate the probability of 2,2,2 distribution.

**It is not easy-peasy.** Both Steves assumed 3 envelopes, not **different , **so (14, 23, 56 );

( 23, 56,14 ); + 4 other permutations counted as one (two, two,two)

Charlie rightly assumed that there are 3 distinct envelopes (say- yellow, green and red) - I do not want to comment **now** about the

final answer - especially re defining "randomly"- will prepare an analytic solution.

My remark re Lord's solution was regarding small typo which affected the final answer, not abouit the basic assumption- i.e. considering the envelopes undistinguishable. I believe his and SH's solutions would be correct , if the word **different** were omitted or disclaimed or the "random" process **strictly defined.**

*Edited on ***January 28, 2019, 7:27 am**