6 cards, labeled 1,2, ...6, are randomly put in 3 different envelopes, at least one card in each.
Evaluate the probability of 2,2,2 distribution.
It is not easy-peasy.
Both Steves assumed 3 envelopes, not different , so (14, 23, 56 );
( 23, 56,14 ); + 4 other permutations counted as one (two, two,two)
Charlie rightly assumed that there are 3 distinct envelopes (say- yellow, green and red) - I do not want to comment now about the
final answer - especially re defining "randomly"- will prepare an analytic solution.
My remark re Lord's solution was regarding small typo which affected the final answer, not abouit the basic assumption- i.e. considering the envelopes undistinguishable. I believe his and SH's solutions would be correct , if the word different were omitted or disclaimed or the "random" process strictly defined.
Edited on January 28, 2019, 7:27 am