All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Sum of reciprocals (Posted on 2019-03-20) Difficulty: 3 of 5
Given

a+b+c+d=0
abcd=1
a3+b3+c3+d3=1983

Find 1/a+1/b+1/c+1/d

No Solution Yet Submitted by Danish Ahmed Khan    
No Rating

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionSolutionBrian Smith2019-03-20 12:31:27
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (7)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information