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| Sum of reciprocals (Posted on 2019-03-20) |
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Given
a+b+c+d=0
abcd=1
a3+b3+c3+d3=1983
Find 1/a+1/b+1/c+1/d
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Subject |
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 | Solution | Brian Smith | 2019-03-20 12:31:27 |
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