Home > Shapes > Geometry
| The midpoint of Tangency (Posted on 2019-04-13) |
 |
In right angled ΔABC, ∠ABC=90 and ∠BCA=60. The incircle of ΔABC touches sides BC and AB at points D and E respectively. Let F be the midpoint of DE. P, Q, R are the feet of perpendiculars from F on BC, CA, AB respectively.
Find (AB+BC+CA)/(PQ+QR+RP).
Comments: (
You must be logged in to post comments.)
|
|
Please log in:
Forums (0)
Newest Problems
Random Problem
FAQ |
About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
|
