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| Four at a time (Posted on 2019-05-16) |
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a1a2a3a4 + a2a3a4a5 + ... + ana1a2a3 = 0 with ai = +1 or -1 for i = 1, 2, 3, ..., n. Show that n is divisible by 4.
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 | Solution | Brian Smith | 2020-05-23 17:16:00 |
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