perplexus.info :: Numbers : Triple cube sum

Triple cube sum (Posted on 2019-06-28)

a+b+c=6
(a-b)/c+(b-c)/a+(c-a)/b=(1+a/b)(1+b/c)(1+c/a)
a²/bc+b²/ca+c²/ab+ab/c²+bc/a²+ca/b²=-2
a³+b³+c³=?

No Solution Yet Submitted by Danish Ahmed Khan

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