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Triple cube sum (Posted on 2019-06-28) Difficulty: 3 of 5
a+b+c=6
(a-b)/c+(b-c)/a+(c-a)/b=(1+a/b)(1+b/c)(1+c/a)
a2/bc+b2/ca+c2/ab+ab/c2+bc/a2+ca/b2=-2
a3+b3+c3=?

No Solution Yet Submitted by Danish Ahmed Khan    
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  Subject Author Date
Solutionre: Some progress - SolutionBrian Smith2019-07-02 18:57:25
Some progressBrian Smith2019-06-30 21:00:24
computer solutionSteven Lord2019-06-28 19:30:31
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