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Recursive reaches one million (Posted on 2019-08-15) Difficulty: 4 of 5
Define a function f mapping positive integers to positive integers by f(1)=1, and f(n)=f(n-1)+n if f(n-1)<=n and f(n)=f(n-1)-n if f(n-1)>n

For n≥2,
i) Find the smallest integer n such that f(n) = 1,000,000
ii) Find the smallest integer n such that f(n) = 2,000,000

No Solution Yet Submitted by Danish Ahmed Khan    
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Re: comp soln Comment 5 of 5 |
we can use generating functions to solve this problem.  If we allowed leading zeros then we could simply use the coefficient of x^45 from the expansion of (1+x+x^2+...+x^9)^10 which turns out to be 432457640.  To eliminate those which have leading zeros we can subtract the coefficient of x^45 from (1+x+x^2+...+x^9)^9 which is 40051495 ( friday night funkin mod game).

Subtracting these two we get
432457640-40051495=392406145

so there are 392,406,145 such 10-digit numbers

  Posted by Luigi Wilcox on 2021-06-25 03:20:35
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