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A special triplet (Posted on 2019-07-02)

For what triplet of positive integers (a,b,c) can the following equation be solvable:

Log(a+b+c)=log(a)+log(b)+log(c)

Assume a<b<c

See The Solution Submitted by Ady TZIDON

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Puzzle Solution

Comment 3 of 3 |

log(a+b+c) = log(a) + log(b)+log(c)

=> log(a+b+c)= log(a*b*c)

=> a+b+c=a*b*c

This equation has appeared in this site before. The solution is given by:

(a, b, c) (- perm {1, 2, 3}

Imposing the restriction a < b < c, we must have:

a=1, b=2, and c=3

Posted by K Sengupta on 2022-06-09 00:20:00

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