A certain convex hexagon is equilateral but
not equiangular. Its opposite sides are also parallel, and separated by distances of 27, 31 and 38.
Find the area of this hexagon.
(In reply to
Some thoughts by broll)
The reason you cannot construct this is your calculated side length is incorrect. It should be slightly larger. Finding this length is the hard part. The area is trivial once you know it.
I tried recreating your construction and I don't see how you are using the pythagorean theorem to find AT. 37/2 and 31/2 are the hypotenuse and leg of a triangle I can see. Likewise for BT.
Its also possible you are assuming the midlines of the parallel sides coincide at a single point O. I'm not sure they must.
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Posted by Jer
on 2020-09-12 12:27:43 |
re: Some thoughts
