Home > Shapes > Geometry
| Image 3D (Posted on 2021-01-05) |
 |
Given is a tetrahedron ABCD in which AB=CD and the sum of measures of the angles BAD and BCD equals 180 degrees. Prove that the measure of the angle BAD is larger than the measure of the angle ADC.
Comments: (
You must be logged in to post comments.)
There are no comments yet.
|
