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Digit ending and divisibility (Posted on 2021-03-03) |
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For some 99-digit number k, there exist two different 100-digit numbers n such that the sum of all natural numbers from 1 to n ends in the same 100 digits as the number kn, but is not equal to it. Prove that k-3 is divisible by 5.
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| nice | Anna Shetty | 2021-07-21 05:57:51 |
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