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Digit ending and divisibility (Posted on 2021-03-03) Difficulty: 3 of 5
For some 99-digit number k, there exist two different 100-digit numbers n such that the sum of all natural numbers from 1 to n ends in the same 100 digits as the number kn, but is not equal to it. Prove that k-3 is divisible by 5.

No Solution Yet Submitted by Danish Ahmed Khan    
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